(3x^2-x+1)(x-1)+x^2(4-3x)=5/2

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Solution for (3x^2-x+1)(x-1)+x^2(4-3x)=5/2 equation: 



(3x^2-x+1)(x-1)+x^2(4-3x)=5/2

We move all terms to the left:

(3x^2-x+1)(x-1)+x^2(4-3x)-(5/2)=0

We add all the numbers together, and all the variables

x^2(-3x+4)+(3x^2-x+1)(x-1)-(+5/2)=0

We get rid of parentheses

x^2(-3x+4)+(3x^2-x+1)(x-1)-5/2=0

We multiply all the terms by the denominator


(x^2(-3x+4))*2+((3x^2-x+1)(x-1))*2-5=0

We move all terms containing x to the left, all other terms to the right

(x^2(-3x+4))*2+((3x^2-x+1)(x-1))*2=5

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